Loop Antenna Design
EECE 690
Designer:Joel M. Krause
Professor:Dr. William Kuhn

This year for EECE 690 the class goal was to design and fabricate a bluetooth receiver on a chip.  The block diagram is shown below with the area that I designed.


My job was to determine if it was feasible to develop a fully integrated loop antenna for the receiver, and then design it.  It was found from the initial research that the radiation resistance of a loop antenna with sides of 2mm was so small compared to the physical resistance of the antenna that the idea of a fully integrated antenna was scrapped.  So I then decided to make a relatively small antenna using a trace on the circuit board. The following discussion is centered around the design of a loop antenna on the circuit board.  The proposed antenna design is shown below.

    Diagram 1: Proposed Antenna Design (black box is the chip (2mm sides) & square around it is the loop antenna (10mm sides))

The following table here shows values that are expected with a change in the distance of one side of the loop antenna (D) and the number of loops in the antenna (N).

The formulas used were:

Because of the Q-enhanced filter that comes after this antenna an output resistance of 1k Ohms is needed for the loop antenna. By placing a matching network after the loop antenna we will be able to boost the radiation resistance and get rid of the XL,, which as seen in the following table is terrible. There is also a 35fF capacitive load that will be seen by the antenna, so I will need to use this load when calculating the matching network. To decide what loop antenna I would use (number of turns and diameter), I had to first make sure that the Q of the antenna was not too big. The on chip Q for the inductors and capacitors cannot be larger than 25. A Q larger than this would make the inductor too large to put on the board. The next restriction was the number of loops that I would need. I decided that too many turns would cause capacitance so I restricted the number of turns to 3. The difference in diameter for an antenna with 1, 2, and 3, loops were 14mm, 10mm, and 9mm respectively for an average Q of 25. Because of the minimal difference in the 2 and 3 loop antenna I chose the 2 loop antenna with the values as shown below.

 
Number of
Diameter
Rant
Inductance
XL
Turns
(m)
(Ohms)
(nH)
(Ohms)
2
0.010
1.5927
30.9916
476.8368


  Table 1:2 Turn Loop Antenna

This is the antenna circuit shown with the matching network.

 

Figure 1: Antenna Circuit and proposed matching network circuit

To get the value for C that will make the matching network have an output resistance of 1k Ohms the following equations were used.

Because we have a value of XL = j476.8 Ohms we will need to put a capacitor in series with the inductor so that we can get the needed XL. Xc needed is -j436.8 Ohms. So now we have:


Figure 2: Antenna Circuit and proposed matching network with Cap to adjust XL.
 

Matching Network

Now need to find the value of the matching network capacitor to get output resistance of 1000 Ohms. Equations are below.

Because of the 35 fF capacitive load we need to subtract the Cp above by 35 fF to get the value needed. Therefore the Cp we need is 1.59 fF.

To find the efficiency of the antenna I needed to first find the physical resistance of the trace used to find an approximate Rphy. Other factors that could change the Rphy could be the resistance in the board as well as the resistance of the bond wires. These values were not calculated because they were very small compared to the resistance of the trace. The trace is approximately 76 mm long, 100 um wide and 10 um thick.


Summary

Problems will occur with the capacitor that is placed to adjust the XL value. The equation for the inductance of the antenna is at best still an approximate. If the inductance of the antenna is different the matching network will not be at the center frequency. This is a huge problem if the antenna is not passing the desired frequency; the whole receiver will not operate. To fix this, the capacitor in series must be tunable off the chip. Once the chip is fabricated and the antenna is placed the capacitor will be tuned to be able to pass the desired frequency. The biggest problem is the size of the capacitor needed for the matching network. In the peregrine process the smallest capacitor that can be used is 10 fF. So the matching network capacitor cannot be placed on the chip. Going from 1.5 Ohms to 1000 Ohms needs a small capacitor. To fix the Rant of 1.5 Ohms a larger loop diameter is needed. Since there is a restriction to the size of the hearing aid, this antenna has to be smaller than approximately 20 mm. I experimented with other values to see if I could come up with a larger matching network capacitor, but to no avail. So unless someone wants to have a loop antenna coming out of his or her ear, the loop antenna is not a good choice for this receiver.

For any questions concerning the preceding document please email me at jkrause@ksu.edu.

For any other questions concerning the receiver in whole please go to www.eece.ksu.edu/~tutor.